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- Consider
and , with and . Then has spectral radius , and , which might go to infinity or zero depending on choice of . (en)
- This is because at , the two stable attractors are , and the unstable attractor is . (en)
- A more general loss function could depend on the entire sequence of outputs, as
for which the problem is the same, just with more complex notations. (en)
- Any activation function works, as long as it is differentiable with bounded derivative. (en)
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