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Lucy Ellen Sewall (26 April 1837 – 13 February 1890) was a 19th-century American physician. She was one of the first women to become a doctor in the United States.

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dbo:abstract
  • Lucy Ellen Sewall (* 26. April 1837 in Roxbury, Massachusetts; † 13. Februar 1890 in Boston, Massachusetts) war eine amerikanische Ärztin. Sie gehörte zu den ersten Frauen, die in den USA Ärztin wurden. (de)
  • Lucy Ellen Sewall (26 April 1837 – 13 February 1890) was a 19th-century American physician. She was one of the first women to become a doctor in the United States. (en)
dbo:birthDate
  • 1837-04-26 (xsd:date)
dbo:birthYear
  • 1837-01-01 (xsd:gYear)
dbo:deathDate
  • 1890-02-13 (xsd:date)
dbo:deathYear
  • 1890-01-01 (xsd:gYear)
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dbo:wikiPageID
  • 67222905 (xsd:integer)
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  • 3113 (xsd:nonNegativeInteger)
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  • 1114563138 (xsd:integer)
dbo:wikiPageWikiLink
dbp:birthDate
  • 1837-04-26 (xsd:date)
dbp:birthPlace
  • Roxbury, Massachusetts, US (en)
dbp:deathDate
  • 1890-02-13 (xsd:date)
dbp:deathPlace
  • Boston, Massachusetts, US (en)
dbp:name
  • Lucy Ellen Sewall (en)
dbp:nationality
  • American (en)
dbp:wikiPageUsesTemplate
dcterms:subject
rdf:type
rdfs:comment
  • Lucy Ellen Sewall (* 26. April 1837 in Roxbury, Massachusetts; † 13. Februar 1890 in Boston, Massachusetts) war eine amerikanische Ärztin. Sie gehörte zu den ersten Frauen, die in den USA Ärztin wurden. (de)
  • Lucy Ellen Sewall (26 April 1837 – 13 February 1890) was a 19th-century American physician. She was one of the first women to become a doctor in the United States. (en)
rdfs:label
  • Lucy Ellen Sewall (de)
  • Lucy Ellen Sewall (en)
owl:sameAs
prov:wasDerivedFrom
foaf:depiction
foaf:isPrimaryTopicOf
foaf:name
  • Lucy Ellen Sewall (en)
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