About: Dana Sue Gray

An Entity of Type: criminal, from Named Graph: http://dbpedia.org, within Data Space: dbpedia.org

Dana Sue Gray (born December 6, 1957) is an American serial killer who murdered three elderly women in 1994. She was caught after a fourth intended victim survived and identified her. Gray says she committed the murders to support her spending habits. She is serving her sentence in the California Women's Prison in Chowchilla.

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dbo:abstract
  • دانا سو غراي (بالإنجليزية: Dana Sue Gray)‏ هي قاتلة متسلسلة أمريكية، ولدت في 6 ديسمبر 1957 في كاليفورنيا الجنوبية في الولايات المتحدة. (ar)
  • Dana Sue Gray (born December 6, 1957) is an American serial killer who murdered three elderly women in 1994. She was caught after a fourth intended victim survived and identified her. Gray says she committed the murders to support her spending habits. She is serving her sentence in the California Women's Prison in Chowchilla. (en)
dbo:apprehended
  • 1994-03-16 (xsd:date)
dbo:birthDate
  • 1957-12-06 (xsd:date)
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  • 14415064 (xsd:integer)
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  • 22878 (xsd:nonNegativeInteger)
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  • 1119138045 (xsd:integer)
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dbp:apprehended
  • 1994-03-16 (xsd:date)
dbp:beginyear
  • 1994-02-16 (xsd:date)
dbp:birthDate
  • 1957-12-06 (xsd:date)
dbp:birthName
  • Dana Sue Armbrust (en)
dbp:birthPlace
dbp:country
  • United States (en)
dbp:endyear
  • 1994-03-16 (xsd:date)
dbp:name
  • Dana Sue Gray (en)
dbp:occupation
  • Former nurse (en)
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dbp:victims
  • 31 (xsd:integer)
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  • دانا سو غراي (بالإنجليزية: Dana Sue Gray)‏ هي قاتلة متسلسلة أمريكية، ولدت في 6 ديسمبر 1957 في كاليفورنيا الجنوبية في الولايات المتحدة. (ar)
  • Dana Sue Gray (born December 6, 1957) is an American serial killer who murdered three elderly women in 1994. She was caught after a fourth intended victim survived and identified her. Gray says she committed the murders to support her spending habits. She is serving her sentence in the California Women's Prison in Chowchilla. (en)
rdfs:label
  • دانا سو غراي (ar)
  • Dana Sue Gray (en)
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foaf:isPrimaryTopicOf
foaf:name
  • Dana Sue Gray (en)
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