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In particle physics the semileptonic decay of a hadron is a decay caused by the weak force in which one lepton (and the corresponding neutrino) is produced in addition to one or more hadrons. An example for this can be K0 → e− + νe + π+ This is to be contrasted with purely hadronic decays, such as K0 → π+ + π−, which are also mediated by the weak force. Semileptonic decays of neutral kaons have been used to study kaon oscillations.

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  • In particle physics the semileptonic decay of a hadron is a decay caused by the weak force in which one lepton (and the corresponding neutrino) is produced in addition to one or more hadrons. An example for this can be K0 → e− + νe + π+ This is to be contrasted with purely hadronic decays, such as K0 → π+ + π−, which are also mediated by the weak force. Semileptonic decays of neutral kaons have been used to study kaon oscillations. (en)
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  • In particle physics the semileptonic decay of a hadron is a decay caused by the weak force in which one lepton (and the corresponding neutrino) is produced in addition to one or more hadrons. An example for this can be K0 → e− + νe + π+ This is to be contrasted with purely hadronic decays, such as K0 → π+ + π−, which are also mediated by the weak force. Semileptonic decays of neutral kaons have been used to study kaon oscillations. (en)
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  • Semileptonic decay (en)
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