About: Hornellsville, New York

An Entity of Type: Administrative divisions of New York, from Named Graph: http://dbpedia.org, within Data Space: dbpedia.org

Hornellsville is a town in Steuben County, New York, United States. The population, not counting the city of Hornell, was 4,039 at the 2020 census. The name is taken from a prominent pioneer family. The Town of Hornellsville is at the western border of the county, and surrounds the city of Hornell. Until 1906, the city of Hornell was named Hornellsville. The name Hornellsville is only used in real estate or legal contexts, but rarely in conversation. This is because Hornell is much more frequently mentioned, and its boundaries are quite different.

Property Value
dbo:PopulatedPlace/areaTotal
  • 112.76808232402945
  • 112.78
dbo:PopulatedPlace/populationDensity
  • 36.0
  • 36.00016526249765
dbo:abstract
  • هورنيلسفيل (بالإنجليزية: Hornellsville, New York)‏ هي بلدة أمريكية تقع في الولايات المتحدة في مقاطعة ستوبين، نيويورك. يقدر عدد سكانها بـ 4,151 نسمة ومساحتها 113.0 كم2 وترتفع عن سطح البحر 365 متر. (ar)
  • Hornellsville Ameriketako Estatu Batuetako inkorporatutako herri bat da. Steuben konderrian kokatuta dago, New York estatuan. 4.151 biztanle ditu, 43,54 kilometro koadroko azaleran banatuta. (eu)
  • Hornellsville is a town in Steuben County, New York, United States. The population, not counting the city of Hornell, was 4,039 at the 2020 census. The name is taken from a prominent pioneer family. The Town of Hornellsville is at the western border of the county, and surrounds the city of Hornell. Until 1906, the city of Hornell was named Hornellsville. The name Hornellsville is only used in real estate or legal contexts, but rarely in conversation. This is because Hornell is much more frequently mentioned, and its boundaries are quite different. (en)
  • Hornellsville es un pueblo ubicado en el condado de Steuben en el estado estadounidense de Nueva York. En el año 2000 tenía una población de 4,042 habitantes y una densidad poblacional de 36 personas por km². (es)
  • Hornellsville est une ville du comté de Steuben, dans l'État de New York, aux États-Unis. En 2010, elle comptait une population de 4 151 habitants. (fr)
  • Hornellsville – miasto w Stanach Zjednoczonych, w stanie Nowy Jork, w hrabstwie Steuben. (pl)
  • Горнеллсвілл (англ. Hornellsville) — місто (англ. town) в США, в окрузі Стубен штату Нью-Йорк. Населення — 4151 особа (2010). (uk)
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  • 112224184.820859 (xsd:double)
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  • 112768082.324029 (xsd:double)
  • 112780000.000000 (xsd:double)
dbo:areaWater
  • 560000.000000 (xsd:double)
  • 569797.384274 (xsd:double)
dbo:elevation
  • 365.000000 (xsd:double)
  • 365.150400 (xsd:double)
dbo:populationDensity
  • 36.000000 (xsd:double)
  • 36.000165 (xsd:double)
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  • 4039 (xsd:nonNegativeInteger)
dbo:subdivision
dbo:timeZone
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  • -5
  • -4
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  • 127222 (xsd:integer)
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  • 10725 (xsd:nonNegativeInteger)
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  • 1114496011 (xsd:integer)
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  • 112.220000 (xsd:double)
dbp:areaLandSqMi
  • 43.330000 (xsd:double)
dbp:areaTotalKm
  • 112.780000 (xsd:double)
dbp:areaTotalSqMi
  • 43.540000 (xsd:double)
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  • 0.560000 (xsd:double)
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  • 0.220000 (xsd:double)
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  • GNIS feature ID (en)
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  • 36 (xsd:integer)
dbp:blankName
dbp:elevationFt
  • 1198 (xsd:integer)
dbp:elevationM
  • 365 (xsd:integer)
dbp:officialName
  • Hornellsville, New York (en)
dbp:popEstAsOf
  • 2021 (xsd:integer)
dbp:populationAsOf
  • 2020 (xsd:integer)
dbp:populationDensityKm
  • 36 (xsd:integer)
dbp:populationDensitySqMi
  • 93.240000 (xsd:double)
dbp:populationEst
  • 4002 (xsd:integer)
dbp:populationTotal
  • 4039 (xsd:integer)
dbp:pushpinMap
  • New York (en)
dbp:pushpinMapCaption
  • Location within the state of New York (en)
dbp:settlementType
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dbp:subdivisionType
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  • EDT (en)
dbp:unitPref
  • Imperial (en)
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  • 42.35 -77.66666666666667
rdf:type
rdfs:comment
  • هورنيلسفيل (بالإنجليزية: Hornellsville, New York)‏ هي بلدة أمريكية تقع في الولايات المتحدة في مقاطعة ستوبين، نيويورك. يقدر عدد سكانها بـ 4,151 نسمة ومساحتها 113.0 كم2 وترتفع عن سطح البحر 365 متر. (ar)
  • Hornellsville Ameriketako Estatu Batuetako inkorporatutako herri bat da. Steuben konderrian kokatuta dago, New York estatuan. 4.151 biztanle ditu, 43,54 kilometro koadroko azaleran banatuta. (eu)
  • Hornellsville is a town in Steuben County, New York, United States. The population, not counting the city of Hornell, was 4,039 at the 2020 census. The name is taken from a prominent pioneer family. The Town of Hornellsville is at the western border of the county, and surrounds the city of Hornell. Until 1906, the city of Hornell was named Hornellsville. The name Hornellsville is only used in real estate or legal contexts, but rarely in conversation. This is because Hornell is much more frequently mentioned, and its boundaries are quite different. (en)
  • Hornellsville es un pueblo ubicado en el condado de Steuben en el estado estadounidense de Nueva York. En el año 2000 tenía una población de 4,042 habitantes y una densidad poblacional de 36 personas por km². (es)
  • Hornellsville est une ville du comté de Steuben, dans l'État de New York, aux États-Unis. En 2010, elle comptait une population de 4 151 habitants. (fr)
  • Hornellsville – miasto w Stanach Zjednoczonych, w stanie Nowy Jork, w hrabstwie Steuben. (pl)
  • Горнеллсвілл (англ. Hornellsville) — місто (англ. town) в США, в окрузі Стубен штату Нью-Йорк. Населення — 4151 особа (2010). (uk)
rdfs:label
  • هورنيلسفيل (نيويورك) (ar)
  • Hornellsville (es)
  • Hornellsville (New York) (eu)
  • Hornellsville, New York (en)
  • Hornellsville (New York) (fr)
  • Hornellsville (pl)
  • Горнеллсвілл (Нью-Йорк) (uk)
owl:sameAs
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  • POINT(-77.666664123535 42.349998474121)
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  • 42.349998 (xsd:float)
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  • -77.666664 (xsd:float)
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  • Hornellsville, New York (en)
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