http://dbpedia.org:8891/sparql?query=define%20sql%3Adescribe-mode%20%22CBD%22%20%20DESCRIBE%20%3Chttp%3A%2F%2Fdbpedia.org%2Fresource%2FCrossbar_theorem%3E&output=application%2Fatom%2Bxml2021-05-16T01:30:15.053562ZOData Service and Descriptor Documenthttp://dbpedia.org/resource/Crossbar_theorem2021-05-16T01:30:15.053562ZIn geometry, the crossbar theorem states that if ray AD is between ray AC and ray AB, then ray AD intersects line segment BC. This result is one of the deeper results in axiomatic plane geometry. It is often used in proofs to justify the statement that a line through a vertex of a triangle lying inside the triangle meets the side of the triangle opposite that vertex. This property was often used by Euclid in his proofs without explicit justification. Some modern treatments (not Euclid's) of the proof of the theorem that the base angles of an isosceles triangle are congruent start like this: Let ABC be a triangle with side AB congruent to side AC. Draw the angle bisector of angle A and let D be the point at which it meets side BC. And so on. The justification for the existence of point D is the often unstated crossbar theorem. For this particular result, other proofs exist which do not require the use of the crossbar theorem.Teorema das barras cruzadasIn geometry, the crossbar theorem states that if ray AD is between ray AC and ray AB, then ray AD intersects line segment BC. This result is one of the deeper results in axiomatic plane geometry. It is often used in proofs to justify the statement that a line through a vertex of a triangle lying inside the triangle meets the side of the triangle opposite that vertex. This property was often used by Euclid in his proofs without explicit justification.Crossbar theoremO teorema das barras cruzadas é um teorema de geometria que se enuncia da seguinte forma: Se o raio AD se situa (angularmente) entre o raio AC e o raio AB, então o raio AD cruza o segmento de reta BC.2339O teorema das barras cruzadas é um teorema de geometria que se enuncia da seguinte forma: Se o raio AD se situa (angularmente) entre o raio AC e o raio AB, então o raio AD cruza o segmento de reta BC.96718938122819741