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<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://www.w3.org/2000/01/rdf-schema#label>	"Relleno con c\u00EDrculos de un tri\u00E1ngulo equil\u00E1tero"@es .
<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://dbpedia.org/ontology/abstract>	"Circle packing in an equilateral triangle is a packing problem in discrete mathematics where the objective is to pack n unit circles into the smallest possible equilateral triangle. Optimal solutions are known for n < 13 and for any triangular number of circles, and conjectures are available for n < 28. A conjecture of Paul Erd\u0151s and Norman Oler states that, if n is a triangular number, then the optimal packings of n \u2212 1 and of n circles have the same side length: that is, according to the conjecture, an optimal packing for n \u2212 1 circles can be found by removing any single circle from the optimal hexagonal packing of n circles. This conjecture is now known to be true for n \u2264 15. Minimum solutions for the side length of the triangle: A closely related problem is to cover the equilateral triangle with a fixed number of equal circles, having as small a radius as possible."@en .
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<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://www.w3.org/2000/01/rdf-schema#comment>	"L'empilement de cercles dans un triangle \u00E9quilat\u00E9ral est un probl\u00E8me d'empilement bidimensionnel dont l'objectif est d'empiler des cercles unit\u00E9s identiques de nombre n dans le triangle \u00E9quilat\u00E9ral le plus petit possible. Des solutions optimales sont connues pour n < 13 et pour tout nombre triangulaire de cercle, et des conjectures sont disponibles pour n < 28. Voici les solutions minimales pour la longueur du c\u00F4t\u00E9 du triangle : Un probl\u00E8me \u00E9troitement li\u00E9 est de couvrir le triangle \u00E9quilat\u00E9ral avec un nombre fixe de cercles \u00E9gaux, ayant un rayon aussi petit que possible."@fr .
<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://dbpedia.org/ontology/abstract>	"L'empilement de cercles dans un triangle \u00E9quilat\u00E9ral est un probl\u00E8me d'empilement bidimensionnel dont l'objectif est d'empiler des cercles unit\u00E9s identiques de nombre n dans le triangle \u00E9quilat\u00E9ral le plus petit possible. Des solutions optimales sont connues pour n < 13 et pour tout nombre triangulaire de cercle, et des conjectures sont disponibles pour n < 28. Une conjecture de Paul Erd\u0151s et Norman Oler indique que si n est un nombre triangulaire alors les empilement optimaux de n \u2212 1 et de n cercles ont la m\u00EAme longueur de c\u00F4t\u00E9 : c'est, selon la conjecture, un empilement optimal pour n \u2212 1 cercles peut \u00EAtre trouv\u00E9 en supprimant un seul cercle de l'empilement hexagonal optimal de n cercles. On sait maintenant que cette conjecture est vraie pour n \u2264 15. Voici les solutions minimales pour la longueur du c\u00F4t\u00E9 du triangle : Un probl\u00E8me \u00E9troitement li\u00E9 est de couvrir le triangle \u00E9quilat\u00E9ral avec un nombre fixe de cercles \u00E9gaux, ayant un rayon aussi petit que possible."@fr .
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<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://dbpedia.org/ontology/abstract>	"\u0417\u0430\u0434\u0430\u0447\u0430 \u0443\u043F\u0430\u043A\u043E\u0432\u043A\u0438 \u043A\u0440\u0443\u0433\u043E\u0432 \u0432 \u043F\u0440\u0430\u0432\u0438\u043B\u044C\u043D\u044B\u0439 \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A \u2014 \u044D\u0442\u043E \u0437\u0430\u0434\u0430\u0447\u0430 \u0443\u043F\u0430\u043A\u043E\u0432\u043A\u0438, \u0432 \u043A\u043E\u0442\u043E\u0440\u043E\u0439 \u0442\u0440\u0435\u0431\u0443\u0435\u0442\u0441\u044F \u0443\u043F\u0430\u043A\u043E\u0432\u0430\u0442\u044C n \u0435\u0434\u0438\u043D\u0438\u0447\u043D\u044B\u0445 \u043E\u043A\u0440\u0443\u0436\u043D\u043E\u0441\u0442\u0435\u0439 \u0432 \u043D\u0430\u0438\u043C\u0435\u043D\u044C\u0448\u0438\u0439 \u043F\u0440\u0430\u0432\u0438\u043B\u044C\u043D\u044B\u0439 \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A. \u041E\u043F\u0442\u0438\u043C\u0430\u043B\u044C\u043D\u044B\u0435 \u0440\u0435\u0448\u0435\u043D\u0438\u044F \u0438\u0437\u0432\u0435\u0441\u0442\u043D\u044B \u0434\u043B\u044F n < 13 \u0438 \u0434\u043B\u044F \u043B\u044E\u0431\u043E\u0433\u043E \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u043E\u0433\u043E \u0447\u0438\u0441\u043B\u0430 \u043A\u0440\u0443\u0433\u043E\u0432. \u0418\u043C\u0435\u044E\u0442\u0441\u044F \u0433\u0438\u043F\u043E\u0442\u0435\u0437\u044B \u0434\u043B\u044F \u0447\u0438\u0441\u043B\u0430 \u043A\u0440\u0443\u0433\u043E\u0432 n < 28. \u0413\u0438\u043F\u043E\u0442\u0435\u0437\u0430 \u041F\u0430\u043B\u0430 \u042D\u0440\u0434\u0451\u0448\u0430 \u0438 \u041D\u043E\u0440\u043C\u0430\u043D\u0430 \u041E\u043B\u0435\u0440\u0430 \u0443\u0442\u0432\u0435\u0440\u0436\u0434\u0430\u0435\u0442, \u0447\u0442\u043E \u0432 \u0441\u043B\u0443\u0447\u0430\u0435, \u043A\u043E\u0433\u0434\u0430 n \u044F\u0432\u043B\u044F\u0435\u0442\u0441\u044F \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u044B\u043C \u0447\u0438\u0441\u043B\u043E\u043C, \u043E\u043F\u0442\u0438\u043C\u0430\u043B\u044C\u043D\u0430\u044F \u0443\u043F\u0430\u043A\u043E\u0432\u043A\u0430 n \u2212 1 \u0438 n \u043A\u0440\u0443\u0433\u043E\u0432 \u0438\u043C\u0435\u0435\u0442 \u043E\u0434\u043D\u0443 \u0438 \u0442\u0443 \u0436\u0435 \u0434\u043B\u0438\u043D\u0443 \u0441\u0442\u043E\u0440\u043E\u043D\u044B. \u0422\u043E \u0435\u0441\u0442\u044C, \u0441\u043E\u0433\u043B\u0430\u0441\u043D\u043E \u0433\u0438\u043F\u043E\u0442\u0435\u0437\u0435, \u043E\u043F\u0442\u0438\u043C\u0430\u043B\u044C\u043D\u043E\u0435 \u0440\u0435\u0448\u0435\u043D\u0438\u0435 \u0434\u043B\u044F n \u2212 1 \u043A\u0440\u0443\u0433\u043E\u0432 \u043C\u043E\u0436\u043D\u043E \u043F\u043E\u043B\u0443\u0447\u0438\u0442\u044C \u043F\u0443\u0442\u0451\u043C \u0443\u0434\u0430\u043B\u0435\u043D\u0438\u0435 \u043E\u0434\u043D\u043E\u0433\u043E \u043A\u0440\u0443\u0433\u0430 \u0438\u0437 \u043E\u043F\u0442\u0438\u043C\u0430\u043B\u044C\u043D\u043E\u0439 \u0448\u0435\u0441\u0442\u0438\u0443\u0433\u043E\u043B\u044C\u043D\u043E\u0439 \u0443\u043F\u0430\u043A\u043E\u0432\u043A\u0438 n \u043A\u0440\u0443\u0433\u043E\u0432. \u041C\u0438\u043D\u0438\u043C\u0430\u043B\u044C\u043D\u044B\u0435 \u043F\u043E \u0434\u043B\u0438\u043D\u0435 \u0441\u0442\u043E\u0440\u043E\u043D\u044B \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A\u0430 \u0440\u0435\u0448\u0435\u043D\u0438\u044F: \u0411\u043B\u0438\u0437\u043A\u0430\u044F \u0437\u0430\u0434\u0430\u0447\u0430 \u2014 \u043F\u043E\u043A\u0440\u044B\u0442\u0438\u0435 \u043F\u0440\u0430\u0432\u0438\u043B\u044C\u043D\u043E\u0433\u043E \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A\u0430 \u0437\u0430\u0434\u0430\u043D\u043D\u044B\u043C \u0447\u0438\u0441\u043B\u043E\u043C \u043A\u0440\u0443\u0433\u043E\u0432 \u0441 \u043A\u0430\u043A \u043C\u043E\u0436\u043D\u043E \u043C\u0435\u043D\u044C\u0448\u0438\u043C \u0440\u0430\u0434\u0438\u0443\u0441\u043E\u043C."@ru .
<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://dbpedia.org/ontology/wikiPageWikiLink>	<http://dbpedia.org/resource/Equilateral_triangle> .
<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://dbpedia.org/property/wikiPageUsesTemplate>	<http://dbpedia.org/resource/Template:Math> .
<http://dbpedia.org/resource/Circle_packing_in_an_equilateral_triangle>	<http://www.w3.org/2000/01/rdf-schema#comment>	"\u0417\u0430\u0434\u0430\u0447\u0430 \u0443\u043F\u0430\u043A\u043E\u0432\u043A\u0438 \u043A\u0440\u0443\u0433\u043E\u0432 \u0432 \u043F\u0440\u0430\u0432\u0438\u043B\u044C\u043D\u044B\u0439 \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A \u2014 \u044D\u0442\u043E \u0437\u0430\u0434\u0430\u0447\u0430 \u0443\u043F\u0430\u043A\u043E\u0432\u043A\u0438, \u0432 \u043A\u043E\u0442\u043E\u0440\u043E\u0439 \u0442\u0440\u0435\u0431\u0443\u0435\u0442\u0441\u044F \u0443\u043F\u0430\u043A\u043E\u0432\u0430\u0442\u044C n \u0435\u0434\u0438\u043D\u0438\u0447\u043D\u044B\u0445 \u043E\u043A\u0440\u0443\u0436\u043D\u043E\u0441\u0442\u0435\u0439 \u0432 \u043D\u0430\u0438\u043C\u0435\u043D\u044C\u0448\u0438\u0439 \u043F\u0440\u0430\u0432\u0438\u043B\u044C\u043D\u044B\u0439 \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A. \u041E\u043F\u0442\u0438\u043C\u0430\u043B\u044C\u043D\u044B\u0435 \u0440\u0435\u0448\u0435\u043D\u0438\u044F \u0438\u0437\u0432\u0435\u0441\u0442\u043D\u044B \u0434\u043B\u044F n < 13 \u0438 \u0434\u043B\u044F \u043B\u044E\u0431\u043E\u0433\u043E \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u043E\u0433\u043E \u0447\u0438\u0441\u043B\u0430 \u043A\u0440\u0443\u0433\u043E\u0432. \u0418\u043C\u0435\u044E\u0442\u0441\u044F \u0433\u0438\u043F\u043E\u0442\u0435\u0437\u044B \u0434\u043B\u044F \u0447\u0438\u0441\u043B\u0430 \u043A\u0440\u0443\u0433\u043E\u0432 n < 28. \u041C\u0438\u043D\u0438\u043C\u0430\u043B\u044C\u043D\u044B\u0435 \u043F\u043E \u0434\u043B\u0438\u043D\u0435 \u0441\u0442\u043E\u0440\u043E\u043D\u044B \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A\u0430 \u0440\u0435\u0448\u0435\u043D\u0438\u044F: \u0411\u043B\u0438\u0437\u043A\u0430\u044F \u0437\u0430\u0434\u0430\u0447\u0430 \u2014 \u043F\u043E\u043A\u0440\u044B\u0442\u0438\u0435 \u043F\u0440\u0430\u0432\u0438\u043B\u044C\u043D\u043E\u0433\u043E \u0442\u0440\u0435\u0443\u0433\u043E\u043B\u044C\u043D\u0438\u043A\u0430 \u0437\u0430\u0434\u0430\u043D\u043D\u044B\u043C \u0447\u0438\u0441\u043B\u043E\u043C \u043A\u0440\u0443\u0433\u043E\u0432 \u0441 \u043A\u0430\u043A \u043C\u043E\u0436\u043D\u043E \u043C\u0435\u043D\u044C\u0448\u0438\u043C \u0440\u0430\u0434\u0438\u0443\u0441\u043E\u043C."@ru .