The 1960 United States presidential election in Rhode Island took place on November 8, 1960, as part of the 1960 United States presidential election, which was held throughout all 50 states. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. Kennedy carried Rhode Island by a margin of 27.27%, making it his strongest state.
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| - 1960 United States presidential election in Rhode Island (en)
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| - The 1960 United States presidential election in Rhode Island took place on November 8, 1960, as part of the 1960 United States presidential election, which was held throughout all 50 states. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. Kennedy carried Rhode Island by a margin of 27.27%, making it his strongest state. (en)
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electoral vote
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| - Jfk2 .jpg (en)
- Unsuccessful 1960.jpg (en)
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| - County Results
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Nixon (en)
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| - Rhode Island Presidential Election Results 1960.svg (en)
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| - The 1960 United States presidential election in Rhode Island took place on November 8, 1960, as part of the 1960 United States presidential election, which was held throughout all 50 states. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island voted for the Democratic nominee, Senator John F. Kennedy of Massachusetts, over the Republican nominee, Vice President Richard Nixon of California. Kennedy ran with Senate Majority Leader Lyndon B. Johnson of Texas, while Nixon's running mate was Ambassador Henry Cabot Lodge, Jr. of Massachusetts. Kennedy carried Rhode Island by a margin of 27.27%, making it his strongest state. (en)
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| - 1960 United States presidential election in Rhode Island (en)
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